An air cored toroidal coil has 3000 turns and carries current 0.1 A.

the length of the magnetic circuit is 30 cm and the cross-sectional area of the coil

is 4cm^2. Determine the:

(i) magnetic field strength;

(ii) magnetic flux density. (6 marks)craft1 electrical June/July 2020

i. To find the magnetic field strength, we can use the formula B = u0 * n * I / l, where B is the magnetic field strength, u0 is the permeability of free space, n is the number of turns in the coil, I is the current in the coil, and l is the length of the magnetic circuit. Plugging in the values given, we get B = (4

pi10^-7 Tm/A) * 3000 turns * 0.1 A / 30 cm = 4.210^-4 T.ii. To find the magnetic flux density, we can use the formula B = u0 * n * I / (A * l), where B is the magnetic flux density, u0 is the permeability of free space, n is the number of turns in the coil, I is the current in the coil, A is the cross-sectional area of the coil, and l is the length of the magnetic circuit. Plugging in the values given, we get B = (4

pi10^-7 Tm/A) * 3000 turns * 0.1 A / (4 cm^2 * 30 cm) = 3.110^-3 T.