A fluorescent lamp tube is filled with a gas containing a mixture of mercury vapour and an inert gas. The gas pressure is 304Pa at 23°C. Determine the gas pressure at 95°C. (4 marks)craft1 electrical June/July 2020

To determine the gas pressure at 95°C, we can use the ideal gas law:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas in kelvin.

Since the volume and number of moles of gas are constant, we can rearrange the formula to solve for P:

P = (nRT) / V

We can substitute the given values into the formula to solve for the gas pressure at 95°C:

P = (n * R * (95°C + 273)) / V = (n * R * 368) / V = (304Pa * 368) / V = 112,192 Pa / V

Since the volume of the gas is constant, the pressure of the gas at 95°C will be proportional to the pressure at 23°C. Therefore, the gas pressure at 95°C will be 112,192 Pa / 304 Pa = 368 times the gas pressure at 23°C.

The gas pressure at 95°C is 368 * 304 Pa = 112,192 Pa.