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Jemshah
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JemshahEnlightened
Asked: January 1, 20232023-01-01T08:55:46+00:00 2023-01-01T08:55:46+00:00In: Applied Science, Electrical Principles 1 And Electronics

An electrical appliance is rated 2 kW and it is operated for 30 minutes. Determine the amount of heat produced. (3 marks)craft1 electrical June/July 2020

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An electrical appliance is rated 2 kW and it is operated for 30 minutes. Determine the amount of heat produced. (3 marks)craft1 electrical June/July 2020

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  1. Jemshah Enlightened
    2023-01-01T08:56:16+00:00Added an answer on January 1, 2023 at 8:56 am

    To find the amount of heat produced by the appliance, we can use the formula Q = P * t, where Q is the amount of heat produced, P is the power of the appliance, and t is the time it is operated. Plugging in the values given, we get Q = 2 kW * 30 minutes = 60 kJ. Note that the power is given in kilowatts and the time is given in minutes, so we will need to convert the power to kilojoules per minute and the time to minutes to get the heat in kilojoules. Since 1 kW = 1000 J/s, 1 kW = 1000 J/s * 1 min/60 s = 16.67 J/s * 1 min = 16.67 J/min. Therefore, 2 kW = 2 * 16.67 J/min = 33.3 J/min. Thus, the amount of heat produced is 60 kJ.

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